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Scipy MCQ's

SciPy stands for?

S Scipy

science library

source library

significant library

scientific library

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Which of the following is not correct sub-packages of SciPy?

S Scipy

scipy.cluster

scipy.source

Explanation

scipy.source is not correct sub-packages of SciPy.

scipy.interpolate

scipy.signal

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Which of the following is true?

S Scipy

By default, all the NumPy functions have been available through the SciPy namespace

There is no need to import the NumPy functions explicitly, when SciPy is imported.

SciPy is built on top of NumPy arrays

All of the above

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What will be output for the following code?

S Scipy

array([ 1. , 2.2, 2.8, 3.4, 4. ])

array([ 1. , 1.6, 2.8, 3.4, 4. ])

array([ 1. , 1.6, 2.2, 2.8, 3.4, 4. ])

Explanation

The above program will generate the following output : array([ 1. , 1.6, 2.2, 2.8, 3.4, 4. ])

array([ 1. , 1.6, 2.2, 2.8, 4. ])

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How to import Constants Package in SciPy?

S Scipy

import scipy.constants

from scipy.constants

Explanation

from scipy.constants is used.

import scipy.constants.package

from scipy.constants.package

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what is constant defined for Boltzmann constant in SciPy?

S Scipy

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What will be output for the following code?

S Scipy

array([ 2., -2., 9., 6.])

array([ 2., -2., 9.])

Explanation

The above program will generate the following output : array([ 2., -2., 9.])

array([ 2., -2.])

array([ 2., -2., 9., -9.])

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In SciPy, determinant is computed using?

S Scipy

determinant()

SciPy.determinant()

det()

Explanation

In SciPy, this is computed using the det() function.

SciPy.det()

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Which of the following is false?

S Scipy

scipy.linalg also has some other advanced functions that are not in numpy.linalg

SciPy version might be faster depending on how NumPy was installed.

Both A and B

None of the above

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What relation is consider between Eigen value (lambda), square matrix (A) and Eign vector(v)?

S Scipy

Av = lambda*v

Explanation

We can find the Eigen values (lambda) and the corresponding Eigen vectors (v) of a square matrix (A) by considering the following relation.

Av =Constant * lambda*v

Av =10 * lambda*v

Av != lambda*v

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Scipy MCQ's

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